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- Mercury is almost two times as dense as iron. (Mercury is twice as dense
as iron)
- Alcohol is 80% of the density of water.
- .

- The density of most objects vary from air which has a density of 0.00129
grams per cubic centimetre (g/cc) to mercury which has a density of
13.60g/cc. Notice that mercury is by far the heaviest with the next
heaviest being iron which is half as dense a mercury. Water provides a
useful benchmark of 1 g/cc, so you can see easily for example that alcohol
is 81% of the density of water.
2.
- His BAC after 1 hour = 0.05398-0.012 x 0.5 = 0.048

- Her BAC is initially 0.1013. The female can drive home after about 4
hours.
- Even though the male and female have drunk the same quantity of alcohol,
the female's BAC is about double the males'. While the male can drive home
after one hour the female has to wait at least 4 hours..
.
-
- The slope of the line from 1977 to 1997 = 0.2 millions of computers
per year; The slope from 1997 to 2050 is 0.12 millions of computers per
year. The rate of increase in computer ownership between 1997 and 2050 is
predicted to be almost half that of 1997 to 1997.
- Let x be the number of kilograms of Coffee A and y be the
number of kilograms of Coffee B. Since there are 60kg altogether, one
equation will be x + y = 60. Each kilo of coffee A costs $15 so the
total for Coffee A will be $12x and each kilo of coffee B is $17 so
the total for coffee B is $17y. The total cost of the coffee will be
60 times $15. So the second equation will be 15x + 17y = 90
x = 24, y = 36

- EZI English increased by 27% while EZI Maths increased by 5.8%, so EZI
English has provided a better return.
- a the mean = $33600, median = $29000 and modal wage
= $12000
b The average wage
is $33 600. For student success I would
use the mean as it looks like the highest number.
c The
standard deviation is 31.0. If the 125 were reduced to 25 this would make the
standard deviation a lot smaller since standard deviation is a measure of spread
from the mean and the data would be less spread out.
7. (i) A = 2000(1 + 0.0525/12) 3
= 2026.37
(ii) A =
2000(1 + 0.0525/12)12 =
3695.88
(iii) Figure 1:
Amount of money in bank over 10 years
amount ($) 
Number of months
7. Solutions
to level C
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